Question

42. Use the Quadratic Equation to find the Roots of x2 + 3x - 3 = 0

Answer 1

Roots: 0.79 and 3.79

Explanation:

`x^2 + 3x - 3 = 0\\a=1\,,\ \ b=3\,,\ \ c=-3\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\x=(-3\pm√(3^2-4\cdot1\cdot(-3)))/(2\cdot1)=(-3\pm√(9+12))/(2)=(-3\pm√(21))/(2)\\\\x\approx0.79\quad or\quad x\approx3.79`