Question

I REALLY NEED HELP!!

The velocity of a car increases from +4.0 m/s to +16.0 m/s
in a time period of 4.0 s. What was the average
acceleration?

Answer 1

The average acceleration of a car that changes its velocity from +4.0 m/s to +16.0 m/s over 4 seconds is 3.0 m/s².

Step-by-step explanation:

The question asks us to determine the average acceleration of a car whose velocity changes from +4.0 m/s to +16.0 m/s over a period of 4.0 seconds. To find the average acceleration, we use the formula:

a = Δv / Δt

where a is the acceleration, Δv is the change in velocity, and Δt is the change in time. The change in velocity (Δv) is the final velocity minus the initial velocity. So, Δv = 16.0 m/s - 4.0 m/s = 12.0 m/s. The time interval (Δt) is 4.0 s.

Now we can plug these values into the formula:

a = Δv / Δt = 12.0 m/s / 4.0 s = 3.0 m/s²

The calculated average acceleration of the car is 3.0 m/s².

Answer 2

Step-by-step explanation:

Although we do have an equation for this in terms of one-dimensional motion, it's easy enough just to use the mathematical definition of acceleration:

`a=(v_f-v_0)/(t)` which says, in words, the acceleration of an object is equal to the objects final velocity minus its initial velocity, divided by the change in time. Since everything is given in m and s, our answer will be in m/s/s:

`a=(16.0-4.0)/(4.0)` and

`a=(12.0)/(4.0)` so

a = 3.0 m/s/s