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Find the value of the test statistic z using z = .

A claim is made that the proportion of children who play sports is less than 0.5, and the sample statistics include n = 1671 subjects with 30% saying that they play a sport.

A. 33.38
B. –33.38
C. 16.35
D. –16.35

User Jamleck
by
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1 Answer

3 votes

Answer:


\sf z = -16.35

formula:


\sf z = \frac{s-p}{\sqrt{(p(1-p))/(n) } }

Here s = 0.3, p = 0.5, n = 1671

solve:


\rightarrow \sf z = \frac{0.30-0.5}{\sqrt{(0.5(1-0.5))/(1671) } }


\rightarrow \sf z = \frac{-0.2}{\sqrt{(0.25)/(1671) } }


\rightarrow \sf z = -16.35

User Zeromus
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