Question

Solve 3y^3 + 12y^2 + 12y =0

Please

Answer 1

y = 0, -2

Explanation:

Factor out the common term 3y.

`3y( {y}^(2) + 4y + 4) = 0`

Rewrite y² + 4y + 4 in the form of a² + 2ab + b², where a = y and b = 2.

`3y( {y}^(2) + 2(y)(2) + {2}^(2) ) = 0`

Use square sum: (a + b)² = a² + 2ab + b².

`3y(y + 2) ^(2) = 0`

solve for y.

y = 0, -2.

therefor, the answer for this equation is 0, - 2.