Question

Cos(0)=2/2 ,and <0<2pi, evaluate sin(0) and tan(0). sin (0)=? tan(0)=?
PLEASE HELP!!!!

Answer 1

Explanation:

using (cosθ)^2 + (sinθ)^2 = 1

2/4 + (sinθ)^2 = 1

sinθ =
`√(2)/2`

or -
`√(2) /2`

By C-A-S-T, sinθ is -ve

sinθ = -
`√(2)/2`

tanθ = sinθ/cosθ = -1

Answer 2

Explanation:

The angle is between 3pi/2 and 2pi so it is in the fourth quadrant where both sin and tan are negative.

Given cos(θ) = sqrt(2)/2

cos^2(θ) + sin^2(θ) = 1

sine^2(θ) = 1 - 2/2^2 = 1 - 1/2 = 1/2

sin(θ) = +/1 sqrt(2)/2

As we know sin(θ) is negative,

sin(θ) = -sqrt(2)/2; the second answer

tan(θ) = sin(θ)/cos(θ) = -1