Answer: The molarity of this solution is 2.5 M.
Step-by-step explanation:
Given :
,
![V_2 = 176 mL](https://img.qammunity.org/2022/formulas/chemistry/high-school/p2nj34b0cozhqhkhamx4159qmqgsf38q0k.png)
![M_1 = 10 M](https://img.qammunity.org/2022/formulas/chemistry/high-school/f8mbeo4el29n4l1i7moy6kywu95mir01c0.png)
Therefore, the value of molarity of the solution is calculated using following formula.
![M_1 * V_1 = M_2 * V_2](https://img.qammunity.org/2022/formulas/chemistry/high-school/cgdaq6tesszw4zf8szve9duyi4oyrlwxd6.png)
Substitute the values into above formula as follows.
![M_1 * V_1 = M_2 * V_2\\10 M * 44 mL = M_2 * 176 mL\\M_2 = (10 M * 44 mL)/(176 mL)\\= 2.5 M](https://img.qammunity.org/2022/formulas/chemistry/high-school/q0gtas6bvbrvhkgs1ajf7k3qbzmdo2eku7.png)
Hence, molarity of the solution is 2.5 M.