Question

What is the change in internal energy if 30 J of heat are released from a

system and the system does 50 J of work on its surroundings?
Use AU= Q-W.

Answer 1

Option B. –80 J

Step-by-step explanation:

From the question given above, the following data were obtained:

Heat (Q) released = –30 J (negative sign because the heat is being released to the surrounding)

Work (W) = 50 J

Change in internal energy (ΔU) =?

We can obtain the change in the internal energy as follow:

ΔU = Q – W

ΔU = –30 – 50

ΔU = –80 J

Therefore, the change in the internal energy is –80 J

Thus, option B gives the correct answer to the question.