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What is the solution set for the equation 2x^2-8x-42=0
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2 votes
What is the solution set for the equation 2x^2-8x-42=0

User Kelend
by
4.3k points

2 Answers

3 votes

Answer:

(-3,7)

Explanation:

User Nizzam
by
4.1k points
2 votes

Answer:

x=−3 or x=7

Explanation:

Step 1: Factor left side of equation.

2(x+3)(x−7)=0

Step 2: Set factors equal to 0.

x+3=0 or x−7=0

x=−3 or x=7

User Midopa
by
4.7k points
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