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PH de un jugo de naranja con [H+]=5.6×10-4M.​
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PH de un jugo de naranja con [H+]=5.6×10-4M.​

User Vincent Durmont
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1 Answer

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Step-by-step explanation:


pH = - log[H {}^( + ) ] \\ = - log(5.6 * {10}^( - 4) ) \\ = 3.25

User Keerigan
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