PH de un jugo de naranja con [H+]=5.6×10-4M.

asked Jan 9, 2022 12.7k views

2 votes

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5 votes

Step-by-step explanation:

$pH = - log[H {}^( + ) ] \\ = - log(5.6 * {10}^( - 4) ) \\ = 3.25$

Keerigan answered Jan 15, 2022

3.1k points

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