Question

2) What is the mass of a sample that produces -1,500 J if the specific heat is 1.0 and the temperature decreases by 30℃?

3) What is the specific heat (C) of silver if we heat a 16g cube from 45 oC to 80 oC and it absorbs 41.3 J of thermal energy?

Answer 1

(2) 50 kg

(3) 73.75 J/kg.K

Step-by-step explanation:

(2) From the question,

Using,

q = mcΔt........................ Equation 1

Where q = amount of heat, m = mass. c = specific heat capacity, Δt = change in temperature

make m the subject of the equation

m = q/(cΔt)..................... Equation 2

Given: q = 1.500 J, c = 1.0 J/kg.K, Δt = 30°C

substitute these values into equation 2

m = 1500/(1×30)

m = 50 kg

(3) using

q = cm(t₂-t₁).

Where t₁ and t₂ = initial and final temperature respectively

making c the subject

c = q/m(t₂-t₁)................ Equation 3

Given: q = 41.3 J, m = 16 g = 0.016 kg, t₂ = 80°C, t₁ = 45°C

Substitute these values into equation 3

c = 41.3/0.016(80-45)

c = 41.3/0.56

c = 73.75 J/kg.K