Answer:
Step-by-step explanation:
By Kirchoff's laws, I1 + I2 = 3
I2 = 3 - I1
Following circuit on the left, V = summation of IRs
9 = I1*3 + 3*2
3*I1 = 9 - 6 = 3
I1 = 1A
I2 = 3 -1 = 2A
Following circuit on the right, V = summation of IRs
ε = I2*4.5 + 3*2
= 2*4.5 + 6
= 15V