Question

calculate the molarity of 0.57 moles NaHCO3 in 61.2 mL of solution. Report your answer 4 places after the decimal don’t forget to round.

Answer 1

The correct response is "9.313 M".

Step-by-step explanation:

According to the question, the values are:

Moles of solute,

= 0.57 moles

Liters of solution,

= 61.2 mL

or,

= 0.0612 L

Now,

The molarity will be:

=
`(Moles \ of \ solute)/(Liters \ of \ solution)`

On putting the given the values in the above formula, we get

=
`(0.57)/(0.0612)`

=
`9.313 \ M`