Question

What is the absolute maximum or minimum of f(x) = 3x^2-5x-9

Answer 1

(5/6,-133/12) You have to use the formula x=-b/2a

Answer 2

Absolute minimum / vertex = (5/6,-133/12)

Explanation:

Since a is positive, then the absolute maximum is ∞. The absolute minimum would be the vertex of the parabola, meaning x=-b/2a=-(-5)/2(3)=5/6, and y=3(5/6)^2-5(5/6)-9 = -133/12. Therefore, your absolute minimum / vertex is (5/6,-133/12)