Question

Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity 132 W/m2 . You may want to review (Pages 897 - 898) . Part A What is the angle from vertical of the axis of the second polarizing filter

Answer 1

θ = 32.4º

Step-by-step explanation:

For this exercise let's use Malus's law

I = Io cos² θ

in this case it indicates that the incident intensity is 370 W/m², when the first polarization passes, only the radiation with the same polarization of the polarizer emerges, that is, vertical

I₀ = 370/2 = 185 W / m²

this is the radiation that affects the second polarizer, let's apply the expression of Maluz

θ = cos⁻¹ (
`\sqrt{(I)/(I_o) }`)

θ = cos⁻¹ (
`√(132/185)`)

θ = cos⁻¹ (0.844697)

θ = 32.4º