Question

a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how high in the air is the skydiver when he opens his parachute after 25 seconds?

Answer 1

5625 feets

Explanation:

Rate(feet/seconds) = height(feets)/time(seconds)

175 = x/25

x = 4375

After the skydiver opens his parachute the height reduces

Initial height – reduced height

10000 – 4375

= 5625 feets

Answer 2

5625 feet

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