Question

The overall efficiency of oxidative phosphorylation, assuming standard conditions, can be calculated by comparing the free energy potentially available from the oxidation of NADH by O2 to the free energy required to synthesize 2.5 ATP from 2.5 ADP. This comparison reveals an efficiency of 35%, which is based on the experimental measurement of 2.5 ATP for every NADH oxidized during oxidative phosphorylation. Using this efficiency, calculate the number of ATP generated by each of the following Complexes:

Answer 1

The number of ATPs produced wheh efficiency is 100% is 71.42 ATP.

Step-by-step explanation:

It is known that at the end of Kreb's cycle 10 NADH are produced

Now by using the unitary method

1 NADH produces=2.5 ATP

10 NADH produces=2.5 ATP x 10

10 NADH produces=25 ATP

This is for the efficiency of 35%.

35% efficiency produces ATPS=25

1% efficiency produced ATP=
`(25)/(35)`

100% efficiency produced ATP=
`(25)/(35)* 100`

100% efficiency produced ATP=71.42 ATP

The number of ATPs produced wheh efficiency is 100% is 71.42 ATP.