Question

A cylinder with a radius of 5 feet and height of 2 feet.

What is the surface area of a cylinder with a radius of 5 ft and a height of 2 ft?
60Pi ft2
70Pi ft2
96Pi ft2
150Pi ft2

Answer 1

the correct answer is 70Pi ft2

using this formula: A=2πrh+2πr2, substitute r for 5 and h for 2 and put it like this:

a = 2π x 5 x 2 + 2π x 5 squared

2 x 5 x 2 = 20

a = 20π + 2π x 5 squared

5 squared = 25

a = 20π + 2π x 25

multiply 2 by 25 which equals 50

a = 20π + 50π

add 20 and 50 which gives you 70 making the final answer: a = 70π ft 2

Answer 2

B, 70pi ft2

Explanation:

The equation to find surface area of a cylinder is 2(pi)(r)(h)+2(pi)(r)^2. So now plug the numbers in.. 2(pi)(5)(2)+2(pi)(5)^2 now, simplify. 20pi+50pi= 70pi ft2.