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AB = 5, AP = 4, and DP = 12, then find the length of PC

User Dhj
by
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1 Answer

5 votes

Answer:


PC = 0.333

Explanation:

Given


AB = 5


AP = 4


DP =12\\

See attachment

Required

Find PC

When two chords intersect, the product of the segments are always equal.

In chord DC, the segments are DP and PC

In chord AB, the segments are AP and PB

So:


DP * PC = AP * PB

This gives:


12 * PC = 4 * PB --- (1)

In chord AB, we have:


AB = AP + PB

Make PB the subject


PB = AB - AP

This becomes


PB = 5 - 4


PB = 1


12 * PC = 4 * PB --- (1) becomes


12 * PC = 4 * 1


12 * PC = 4

Make PC the subject


PC = (4)/(12)


PC = 0.333

AB = 5, AP = 4, and DP = 12, then find the length of PC-example-1
User Irfan Harun
by
6.4k points