Question

What is the volume, in liters, of 0.350 mol of nitrogen gas at 32°C and

0.980 atm of pressure? *
A. 9.85 L
B. 8.94 L
C. 104.6 L
D. 0.94 L

Answer 1

Answer: The volume is 8.94 L.

Step-by-step explanation:

Given: no. of moles = 0.350 mol, Pressure = 0.980 atm

Temperature =
`32^(o)C = (32 + 273) K = 305 K`

Formula used to calculate the volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

`PV = nRT\\0.980 atm * V = 0.350 mol * 0.0821 L atm/mol K * 305 K\\V = 8.94 L`

Thus, we can conclude that the volume is 8.94 L.