Answer:
51
1−2+3−4+5−.....+101
=(1+3+5+.....+101)−(2+4+6+.....+100)
=(1+3+5+.....+101)−2(1+2+3+.....+50)
=(51)
2
−2(
50(50+1)
)
=2601−2×1275
=2601−2550
=51
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