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Find value of X in cos(3x-30°)=sin(7x+50°)​

1 Answer

3 votes

Answer:

7

Explanation:

Given the expression

cos(3x-30°)=sin(7x+50°)

In trigonometry cosx = sin(90-x)

Hence

Cos(3x-30) = sin(90-(3x-30))

Cos (3x-30) = sin(90-3x+30)

Cos (3x-30) = sin(120-3x)

Substitute into the expression above

Sin(120-3x) = sin(7x+50)

120-3x = 7x+50

Collect like terms

-3x-7x = 50-120

-10x = -70.

x = 70/10

x = 7

Hence the value of x is 7

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