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Find the magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, –2).

A: 0
B: 13
C: 8
D:16


User Ove S
by
7.2k points

1 Answer

4 votes

Answer:

B

Explanation:

Use the distance formula in 3 dimensions

d =
\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2+(z_(2)-z_(1))^2 }

with (x₁, y₁, z₁ ) = (3, 4, 10) and (x₂, y₂, z₂ ) = (8, 4, - 2)

d =
√((8-3)^2+(4-4)^2+(-2-10)^2)

=
√(5^2+0^2+(-12)^2)

=
√(25+144)

=
√(169)

= 13 → B

User DKean
by
6.6k points