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A 1200 kg car accelerates from rest to 10.0 m/s in a time of 4.50 seconds. Calculate the force that the car’s tires exerted on the road.

please help me i need the answer in 10 mins

User Cambium
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1 Answer

6 votes

Answer:

the force that the car’s tires exerted on the road is 2,666.67 N.

Step-by-step explanation:

Given;

mass of the car, m = 1,200 kg

initial velocity of the car, u = 0

final velocity of the car, v = 10.0 m/s

time of motion, t = 4.50 s

The force the car’s tires exerted on the road is calculated as follows;


F = ma= (m(v-u))/(t) \\\\F = (1200(10-0))/(4.5) \\\\F = 2,666.67 \ N

Therefore, the force that the car’s tires exerted on the road is 2,666.67 N.

User Blackp
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