Question

Find the average acceleration of a northbound subway train that slows down from 12 m/s to 9.6 m/s in 0.8 seconds.​

Answer 1

`a=-3\ m/s^2`

Step-by-step explanation:

Given that,

Initial speed of a train, u = 12 m/s

Final speed of a train, v = 9.6 m/s

Time taken, t = 0.8 s

We need to find the average acceleration of the train. We know that the rate of change of velocity is equal to acceleration. So,

`a=(v-u)/(t)\\\\a=(9.6-12)/(0.8)\\\\a=-3\ m/s^2`

So, the average acceleration of the train is equal to
`-3\ m/s^2`.