Question

If a team of minors drill a hole 50.4 m into a rock formation and drill at a steady rate of 2.8 m/min. how long does it take to drill the hole

Answer 1

t = 18 minutes.

Explanation:

We can find the time by using the following kinematic equation:

`y_(f) - y_(0) = v_(0)t + (1)/(2)at^(2)`

`\Delta y = v_(0)t + (1)/(2)at^(2)`

Where:

Δy: is the difference between the initial and the final height = 50.4 m

t: is the time

a: is the acceleration

v₀: is the velocity of the drill = 2.8 m/min

Since the speed of perforation is constant, the acceleration is zero so:

`\Delta y = v_(0)t`

Then, by solving the above equation for "t" we have:

`t = (\Delta y)/(v_(0)) = (50.4 m)/(2.8 m/min) = 18 min`

Therefore, it takes 18 minutes to drill the hole.

I hope it helps you!