Question

Find the equation of the straight line having a slope root 3 and passing through the point(-1,5)​

Answer 1

Given:

Slope of a straight line is
`√(3)`.

The line passing through the point (-1,5).

To find:

The equation of the straight line.

Solution:

The point slope form of a line is:

`y-y_1=m(x-x_1)`

Where, m is the slope and
`(x_1,y_1)` is the point.

The line passing through the point (-1,5) with slope
`√(3)`. So, the equation of the line is:

`y-5=√(3)(x-(-1))`

`y-5=√(3)(x+1)`

`y=√(3)x+√(3)+5`

Therefore, the equation of the straight line is
`y=√(3)x+√(3)+5`.