Question

One gallon of gasoline (C8H18) weights about 6.3 pounds. Burning gasoline with excess of oxygen forms water and carbon dioxide. When 3.1 gallons of gasoline burn, how many pounds of CO2 emit into the air?

FW: C = 12; H = 1; O = 16.

Answer 1

60 pounds of CO₂ are emited into the air

Step-by-step explanation:

The combustion of gasoline occurs as follows:

C₈H₁₈(l) + 25/2O₂(g) ⇄ 8CO₂(g) + 9H₂O

Where 1 mole of gasoline produce 8 moles of CO₂

To solve this question we must find the moles of gasoline in 3.1 gallons. 8 times these moles are the moles of CO₂ produced. With the moles of CO₂ we can find its pounds as follows:

Pounds gasoline:

3.1 gallons * (6.3 pounds / gallon) = 19.53 pounds

Grams gasoline:

19.53 pounds * (453.592g / pound) = 8859g

Moles gasoline -Molar mass C8H18: 114.23g/mol-

8859g * (1mol / 114.23g) = 77.55 moles gasoline

Moles CO₂:

77.55 moles gasoline * (8 mol CO₂ / mol Gasoline) = 620.4 moles CO₂

Mass CO₂ - Molar mass: 44.01g/mol-

620.4 moles CO₂ * (44.01g / mol) = 27304g CO₂

Pounds CO₂:

27304g CO₂ * (1lb / 453.592g) =

60 pounds of CO₂ are emited into the air