Answer:
0.24 M
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O
From the balanced equation,
The mole ratio of the acid, H₂SO₄ (nₐ) = 1
The mole ratio of the base, NaOH (n₆) = 2
Finally, we shall determine the molarity of the acid. This can be obtained as follow:
Volume of acid, H₂SO₄ (Vₐ) = 17.4 mL
Molarity of base, NaOH (M₆) = 0.20 M
Volume of base, NaOH (V₆) = 41.51 mL
Molarity of acid, H₂SO₄ (Mₐ) =?
MₐVₐ / M₆V₆ = nₐ / n₆
Mₐ × 17.4 / 0.2 × 41.51 = 1 / 2
Mₐ × 17.4 / 8.302 = 1 / 2
Cross multiply
Mₐ × 17.4 × 2 = 8.302
Mₐ × 34.8 = 8.302
Divide both side by 34.8
Mₐ = 8.302 / 34.8
Mₐ = 0.24 M
Therefore, the molarity of the acid is 0.24 M