Question

a balloon rubbed against denim gains a charge of -8.0 x 10^-6 c. What is the electric force between the balloon and the denim, which now has a charge of +8.0 × 10^-6 C, when the two are separated by a distance of 0.05 m?​

Answer 1

230.4 N

Step-by-step explanation:

Applying,

F = kqq'/r²..................... Equation 1

Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.

From the question,

Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²

F = (576×10⁻³)/0.0025

F = 230.4 N.