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5

Which of the following is the result of expanding 22"-2,
n=1
O 8.5
O 15.5
O 32
60

5 Which of the following is the result of expanding 22"-2, n=1 O 8.5 O 15.5 O-example-1

2 Answers

2 votes

Answer:

Answer is B edg2021

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User Thales Valias
by
7.1k points
2 votes

Answer:


\sum\limits^5_(n=1) {2^(n-2)} = 15.5

Explanation:

Given


\sum\limits^5_(n=1) {2^(n-2)

Required

The result

To do this, we simply substitute 1 to 5 for n.

So, we have:


\sum\limits^5_(n=1) {2^(n-2)} = 2^(1-2) + 2^(2-2) + 2^(3-2) + 2^(4-2) + 2^(5-2)


\sum\limits^5_(n=1) {2^(n-2)} = 2^(-1) + 2^(0) + 2^(1) + 2^(2) + 2^(3)

Evaluate each exponent


\sum\limits^5_(n=1) {2^(n-2)} = 0.5 + 1 + 2 + 4 +8


\sum\limits^5_(n=1) {2^(n-2)} = 15.5

User Mdunisch
by
7.2k points