Question

A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla. What is the magnitude force (in N) on the molecule?

Answer 1

3.591 N

Step-by-step explanation:

Applying,

F = Bvq................. Equation 1

Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.

From the question,

Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s

Substitute these values into equation 1

F = 0.57×9×10⁻⁸×7×10⁷

F = 35.91×10⁻¹

F = 3.591 N

Hence the force on the molecule is 3.591 N