54.8k views
2 votes
Solve for the missing side lengths indicated by the question mark.

Solve for the missing side lengths indicated by the question mark.-example-1
User Anthr
by
7.8k points

1 Answer

7 votes

Answer:

6; 40

Explanation:

Problem 1:

Based on the triangle similarity theorem, we would have the following equation:

Let the missing side length = x

Thus:

(15 + x)/15 = 14/(14 - 4)

(15 + x)/15 = 14/10

(15 + x)/15 = 7/5

Cross multiply

5(15 + x) = 7*15

75 + 5x = 105

5x = 105 - 75

5x = 30

x = 30/5

x = 6

Missing side = 6

Problem 2:

Applying similarly theorem also, we have:

Let the missing side = x

x/(x - 25) = 24/(24 - 15)

X/(x - 25) = 24/9

x/(x - 25) = 8/3

Cross multiply

x*3 = 8(x - 25)

3x = 8x - 200

3x - 8x = -200

-5x = -200

x = -200/-5

x = 40

Missing side = 40

User Damitha Raveendra
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories