Question

Using this formula Q = mcAt. A 1kg block of aluminum is increased in temperature by 75°C. how much heat energy was required? a 67,7250 b 67.728 C 65.7253 d 66.7253 Check it​

Answer 1

67500 J

Step-by-step explanation:

Q = mcΔt.................... Equation 1

Where Q = Amount of heat, m = mass of aluminum, c = specific heat capacity of aluminium, Δt = change or increase in temperature.

From the question,

Given: m = 1 kg, Δt = 75 °C

Constant: c = 900 J/kg.K

Substitute these values into equation 1

Q = 1×900×75

Q = 67500 J

Hence the heat energy required is 67500 J