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5 votes
The x-coordinate of the vertex of the function y=-x²+bx+3 is 10. Determine the y-coordinate of the vertex.

2 Answers

5 votes

Answer:

  • 103

Explanation:

Given function:

  • y = -x² + bx + 3

The x-coordinate of a quadratic function y = ax² + bx + c is determined by:

  • x = -b/2a

The given function has:

  • x = 10, and a = -1

Find the value of b:

  • 10 = -b / -2
  • b = 20

The function is:

  • y = -x² + 20x + 3

The y-coordinate of the vertex is:

  • y = -(10²) + 20*10 + 3 = -100 + 200 + 3 = 103
User Ben Taliadoros
by
8.6k points
4 votes

Answer:

Solution given:

y = -x² + bx + 3

we have

The x-coordinate of a quadratic function y = ax² + bx + c is determined by:

x =
( - b)/(2a)

we have

x = 10, and a = -1

Substituting value of a in -b/2a

we get

b = 20

now

The y-coordinate of the vertex is:

y = -(10²) +20*10+ 3 = -100 + 200 + 3 = 103 is your answer.

User Mark Struzinski
by
8.1k points

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