Question

Using the ideal gas law, what will be the volume occupied by 1.46 moles of helium at

0.982 atmospheres and 13.0°C? (R = 0.0821 L'atm/mol-K)

Answer 1

34.91 L

Step-by-step explanation:

Ideal gas law -> PV=nRT

convert C to K -> 13+273 = 286

plug numbers in

(.982)V=(1.46)(.0821)(286)

V = 34.91 L