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A box contain 10 green pins 3 are blue and 7 are green. Two pins are randomly taken out of the box without replacement work out the probability that both pins are the same color

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Answer:


P(Z)=(8)/(15)

Explanation:

From the question we are told that:

Sample size
n=10

Green pins
x=7

Blue pins
y=3

Generally the probability of getting two green is mathematically given by


P(2X)=(7)/(10)*(6)/(9)


P(2X)=(7)/(15)

Generally the probability of getting two blue is mathematically given by


P(2Y)=(3)/(10)*(2)/(9)


P(2Y)=(1)/(15)

Therefore the probability that both pins are the same color P(Z)


P(Z)=P(2Y)+P(2X)\\P(Z)=(7)/(15)+(1)/(15)


P(Z)=(8)/(15)

User Vijayendra Bapte
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