Question

20.

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A(n)=-6+(n-1)(
`(1)/(5)`)

A. –6,
`-5(2)/(5)`,
`-4(1)/(5)`

B. 0,
`(3)/(5)`, 1
`(4)/(5)`

C. –6, -5
`(1)/(5)`, -4

D. 5, -5
`(1)/(5)`, 1
`(4)/(5)`

Answer 1

A. –6, ,

Explanation:

answer is D. -6, -5 2/5, -4 1/5

A(1)=-6+(1-1)(1/5) = -6 + 0 = -6

A(4)=-6+(4-1)(1/5) = -6 + 3/5 = - 5 2/5

A(10)=-6+(10-1)(1/5) = -6 + 9/5 = -4 1/5

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