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What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance

User Anatoly E
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1 Answer

2 votes

Answer:

New force = 9(initial force)

Step-by-step explanation:

The force between two charges is given by :


F=(kq_1q_2)/(r^2)

Where

d is the original distance

Let d' is the new distance such that, r' = r/3

New force,


F'=(kq_1q_2)/(r'^2)\\\\F'=(kq_1q_2)/(((r)/(3))^2)\\\\F'=9* (kq_1q_2)/(r^2)\\\\F'=9F

So, the new force becomes 9 times the initial force.

User DivineDesert
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