What is sec 0 when cot 0 = -4/2?

asked Feb 5, 2022 45.2k views

5 votes

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5 votes

Answer:

sec 0=(√(66) )/(8)

Explanation:

Cot0=-4√(2)

sec0=(√(33) )/(4√(2) )

=(√(33) )/(4√(4) ) *(4√(2) )/(4√(2) )

=(4√(66) )/(32)

=(√(66) )/(8)

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hope it helps...

have a great day!!

Oleksandr Gubchenko answered Feb 12, 2022

6.6k points

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