Question

What type of bond would be formed between nitrogen (N) and nitrogen (N)? Why?

an ionic bond because there is less than a 0.4 difference in electronegativity between the atoms

a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms

a nonpolar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms

Answer 1

Answer: The compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.

Step-by-step explanation:

If electronegativity difference between two atoms is less than 0.4 then bond formed is a pure covalent bond.

If electronegativity difference between two atoms is between 0.4 to 1.8 then bond formed is a polar covalent bond.

If electronegativity difference between two atoms is greater than 1.8 then bond formed is an ionic bond.

The electronegativity value of a nitrogen atom is 3.04. Hence, the electronegativity difference of
`N_(2)` molecule is as follows.

`Electronegativity difference = electronegativity value of N - electronegativity value of N\\= 3.04 - 3.04\\= 0`As the electronegativity difference is 0 which is less than 0.4.

Hence, we can conclude that the compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.