Question

Question 2-4 please

Answer 1

Explanation:

2) a) You have to find the area of semicircle.

r = d/2 = 12/2 = 6 mm

Area of semicircle =
`(1)/(2)\pi r^(2)`

`= (1)/(2)*3.14*6*6\\\\= 3.14*3*6\\\\= 56.52 mm^(2)`

b) r = 10 cm

Area of quadrant =
`(1)/(4)\pi r^(2)`

`= (1)/(4)*3.14*10*10\\\\=3.14*5*5\\\\= 78.5 cm^(2)`

3) d = 10 m

r = d/2 = 10/2 = 5 m

Area of circular garden = πr²

= 3.14 * 5 * 5

= 78.5 m²

Area of rectangular pool = 8 * 6 = 48 m²

Area of the garden covered in grass = area of the circular garden - area of pool

= 78.5 - 48

= 30.5 m²

4) a) r = 60 cm

Area of the top of the circular table = πr²

= 3.14 * 60 * 60

= 11304 cm²

diameter of base = 30 cm

r = 30/2 = 15 cm

Area of circular base = 3.14 * 15 * 15

= 706.5 cm²