Answer:
150°
Explanation:
Construct a line OC, and consider the resulting triangles ΔOAC.
<AOB=(1/2)x
<CAO=90
<ACO=30/2=15
Angles in a triangle add to 180, so
90+15+(x/2)=180
x/2=75
x=150°
Consider OACB,
Here <CAO =<CBO= 90° ( As they are tangents)
<ACB= 30°
Now, <CAO +<CBO+<ACB+x= 360°
90°+90°+30°+x= 360°
x= 150°
Hope it helps
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