Question

Y=(x)^2+10x-12 find the vertex form

Answer 1

y=(x+5)^2-27

Vertex =(−5,−27)

Explanation:

y=x^2+10x-2

y=x^2+10x+ 25-25 -2

y=(x^2+10x+25)-27

y=(x+5)(x+5)-27

y=(x+5)^2-27

Vertex =(−5,−27)

This is the right answers from deltamath

Answer 2

(-5,-37)

Explanation:

While the standard quadratic form is a x 2 + b x + c = y , the vertex form of a quadratic equation is y = a ( x − h ) 2 + k . In both forms, y is the y -coordinate, x is the x -coordinate, and a is the constant that tells you whether the parabola is facing up ( + a ) or down ( − a ).