Question

15.

A tank containing 173 grams of methane, CH (9), registers 15.1 atmospheres at 298 Kelvin. What is the volume of the tank (assuming the entire volume is available to the gas)?
A 3,410L
B. 213
C.O 175L
D. 280.
Chemistry 4/28 5454
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Answer 1

Answer: The volume of tank is 17.5 L.

Step-by-step explanation:

Given: Mass of methane = 173 g

Pressure = 15.1 atm

Temperature = 298 K

Molar mass of methane is 16.04 g/mol.

Therefore, moles of methane are calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (173 g)/(16.04 g/mol)\\= 10.78 mol`

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

`PV = nRT\\15.1 atm * V = 10.78 mol * 0.0821 L atm/mol K * 298 K\\V = (10.78 mol * 0.0821 L atm/mol K * 298 K)/(15.1 atm)\\= 17.5 L`

Thus, we can conclude that volume of the tank is 17.5 L.