Answer: (x − 3)2 + y2 = 5
a. (x + 3)2 + y2 = 5
b. (x − 3)2 + y2 = 25
c. (x − 3)2 + y2 = 5
d. (x + 5)2 + ( y + 1)2 = 25
Explanation:
Begin by determining the length of the radius for the circle. A radius is a line segment from the center of the circle to any point on the circle. Find the length of the radius using the Distance Formula.
r= √(x2 − x1)2 + (y2 − y1)2
Substitute the given values for the center of the circle and the point on the circle into the distance formula and solve for r.
r= √( 5− 3)2 + (1 − 0)2
= √22 + 12
= √4 + 1
= √5
So, the length of the radius is √5 units.
The equation of a circle with center (h, k) and radius r is (x − h)2 + (y − k)2 = r2. Substitute the value for the radius and the coordinates of the center of the circle into the equation.
(x − 3)2 +(y − 0)2 = (√5)2
Simplify.
(x − 3)2 + y2 = 5 Therefore, the equation of the circle B that passes through (5, 1) and has center (3, 0) is (x − 3)2 +y2 = 5.