A balloon at -73C with 5L of gas is heated to 400K. If the pressure ranges from 101.3 kPa to 1520 torr; What will be the final volumn

Question

asked Oct 5, 2022 149k views

1 Answer

Rnaud · Answer 1 · 2022-10-10T06:06:43+0000

Answer: The final volume will be 2.89 L.

Step-by-step explanation:

Given:
T_(1) = 73^(o)C = (73 + 273) K = 346 K ,
V_(1) = 5L ,
T_(1) = 400 K

P_(1) = 101.3 kPa

Convert kPa to atm as follows.

$1 kPa = 0.00986923\\101.3 kPa = 101.3 kPa * (0.00986923 atm)/(1 kPa)\\= 0.99 atm\\= 1 atm$

P_(2) = 1520 torr

Convert torr into atm as follows.

$1 torr = 0.00131579 atm\\1520 torr = 1520 torr * (0.00131579 atm)/(1 torr)\\= 2 atm$

Formula used to calculate final temperature is as follows.

(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))

Substitute the values into above formula as follows.

$(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))\\(1 atm * 5 L)/(346 K) = (2 atm * V_(2))/(400 K)\\V_(2) = 2.89 L$

Thus, we can conclude that the final volume will be 2.89 L.