Question

Which of the following are solutions to the equation below?

Check all that apply.
X^2-3x+ 27 = 6x + 7

Answer 1

♪Answer :

»x² - 3x + 27 = 6x + 7

• ax² + bx + c = 0

»x² - 3x + 27 - 6x - 7 = 0

»x² - 9x + 20 = 0

»(x - 4)(x - 5) = 0

»(x - 4) = 0 V (x - 5) = 0

• For
  `\tiny x_1`

»x - 4 = 0

»x = 0 + 4

»x = 4

• For
  `\tiny x_2`

»x - 5 = 0

»x = 0 + 5

»x = 5

• x = x

Answer 2

`\\ \rm\bull\rightarrowtail x^2-3x+27=6x+7`

`\\ \rm\bull\rightarrowtail x^2-3x-6x+27-7=0`

`\\ \rm\bull\rightarrowtail x^2-9x+20=0`

`\\ \rm\bull\rightarrowtail x^2-5x-4x+20=0`

`\\ \rm\bull\rightarrowtail x(x-5)-4(x-5)=0`

`\\ \rm\bull\rightarrowtail (x-4)(x-5)=0`

`\\ \rm\bull\rightarrowtail x=4,5`