Question

Fizik

Dua perintang 5 Ω dan 10 Ω disambung selari dengan 9 V bekalan kuasa. Kira kuasa output bekalan kuasa.​

Answer 1

P = 24.32 W

Step-by-step explanation:

The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".

The voltage of the power supply, V = 9 V

Resistor 1, R₁ = 5 Ω

R₂ = 10 Ω

The equivalent of parallel combination of resistors is given by :

`(1)/(R_(eq))=(1)/(R_1)+(1)/(R_2)\\\\(1)/(R_(eq))=(1)/(5)+(1)/(10)\\\\R_(eq)=3.33\ \Omega`

The power of the output is given by :

`P=(V^2)/(R_(eq))\\\\=(9^2)/(3.33)\\\\P=24.32\ W`

So, the output power is equal to 24.32 W.