Answer:
1. Moles of oxygen required to react with 5 moles of C₈H₁₈ = = 62.5 moles of oxygen
2. Mass of oxygen required = 2000 g of oxygen
3. Moles of CO₂ that will be produced = 40 moles of CO₂
4. Mass of CO₂ that will be produced = 1760 g of CO₂
5. Moles of H₂O that will be produced = 45 moles of H₂O
Step-by-step explanation:
Balanced equation of the reaction : 2 C₈H₁₈ + 25 O₂ ---> 16 CO₂ + 18 H₂O
1. Mole ratio of Oxygen and C₈H₁₈ = 25 : 2
Moles of oxygen required to react with 5 moles of C₈H₁₈ = 5 × 25/2 moles
Moles of oxygen required to react with 5 moles of C₈H₁₈ = = 62.5 moles of oxygen
2. Mass of oxygen required = number of moles of oxygen × molar mass of oxygen
Molar mass of oxygen = 32.0 g/mol
Mass of oxygen required = 62.5 moles × 32.0 g/mol
Mass of oxygen required = 2000 g of oxygen
3. Mole ratio of CO₂ and C₈H₁₈ = 16 : 2
Moles of CO₂ that will be produced = 5 × 16/2 moles
Moles of CO₂ that will be produced = 40 moles of CO₂
4. Mass of CO₂ that will be produced = number of moles of CO₂ × molar mass of CO₂
Molar mass of CO₂ = 44.0 g/mol
Mass of CO₂ that will be produced = 40 moles × 44 g/mol
Mass of CO₂ that will be produced = 1760 g of CO₂
5. Mole ratio of H₂O and C₈H₁₈ = 18 : 2
Moles of H₂O that will be produced = 5 × 18/2 moles of H₂O
Moles of H₂O that will be produced = 45 moles of H₂O