353,169 views
4 votes
4 votes
Can you guys help? Hopefully the last question of the day/night!

Can you guys help? Hopefully the last question of the day/night!-example-1
User Parth Chavda
by
2.7k points

2 Answers

26 votes
26 votes
Answer and explain: 1st person: 70% throws 70/100x80 = 56 out of 80 throws 2nd person: 60% throws 60/100x80 = 48 out of 80 throws 3rd person 50% throws 50/100x80 = 40 out of 80 throws 56+ 48+40/80x3 = 77/120 One equation that gives the estimated number of free throws (all the 3 people) is 77 out of 120. The best player will make about 56 out of 80 free throws.
User Stalfos
by
2.7k points
12 votes
12 votes

Answer and explain:

1st person: 70 % throws

70/100x80 = 56 out of 80 throws

2nd person: 60% throws

60/100x80 = 48 out of 80 throws

3rd person 50% throws

50/100x80 = 40 out of 80 throws

56+48+40/80x3 = 77/120​

One equation that gives the estimated number of free throws (all the 3 people) is 77 out of 120. The best player will make about 56 out of 80 free throws.

User German Quinteros
by
3.2k points